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16x^2-64x=36
We move all terms to the left:
16x^2-64x-(36)=0
a = 16; b = -64; c = -36;
Δ = b2-4ac
Δ = -642-4·16·(-36)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-80}{2*16}=\frac{-16}{32} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+80}{2*16}=\frac{144}{32} =4+1/2 $
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